If 5 ^2x+1 ÷25= 125 find the value of x.
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Step-by-step explanation:
Given:-
5^(2x+1)÷25 = 125
To find:-
Find the value of x?
Solution:-
Given that
5^(2x+1)÷25 = 125
=> 5^(2x+1)÷5^2 = 5^3
=> 5^(2x+1) / 5^2 = 5^3
We know that
a^m / a^n = a^(m-n)
Where a = 5 and m = 2x+1 and n = 2
=> 5^(2x+1-2) = 5^3
=>5^(2x-1) = 5^3
Since the bases are equal then exponents must be equal.
=> 2x-1 = 3
=>2x = 3+1
=>2x = 4
=>x = 4/2
=>x = 2
Answer:-
The value of x for the given problem is 2
Check:-
If x = 2 then LHS
5^(2x+1)÷25
= 5^(2×2+1)÷25
=5^(4+1)÷25
=> 5^5÷25
=>5^5÷5^2
=> 5^(5-2)
=>5^3
=>5×5×5
=125
=RHS
LHS = RHS is true for x=2
Used formula:-
- a^m / a^n = a^(m-n)
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