Question

If 5^2x+1÷25 = 125,find the value of x

Answer 1

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${5}^{2x + 1} \div 125 = 125$

$\frac{ {5}^{2x + 1} }{125} = 125$

$\frac { {5}^{2x + 1} }{ {5}^{3} } = {5}^{3}$

${5}^{2x + 1} = {5}^{3} \times {5}^{3}$

${5}^{2x + 1} = {5}^{3 + 3}$

${5}^{2x + 1} = {5}^{6}$

$2x + 1 = 6$

$2x = 6 - 1$

$2x = 5$

$x = \frac{5}{2}$