Math, asked by KishoreMSD7, 9 months ago

if (5^2x+2)-625=4.5^2x+1 Find value of x Pls tell fast

Answers

Answered by sulekhashaw24
0

Answer:

25^x-1 = 5^(2x-1) - 100

⇒ 5^2x-2 = 5^(2x-1) - 100

⇒ 5^2x-2 - 5^2x-1 = -100

⇒ 5^2x [ 5^-2 - 5^-1] = - 100

⇒ 5^2x [ 1 - 1 ] = - 100

25 5

⇒ 5^2x [ 1 - 5] = - 100

25

⇒ 5^2x [ -4 ] = - 100

25

⇒ 5^2x [-4] = -100 * 25

⇒ 5^2x = 100 * 25 [ - * - = +]

4

⇒ 5^2x = 625

⇒ 5^2x = 5^4

so, ⇒ 2x = 4

⇒ x = 2

Answered by javales0911
0

Answer:

I'm not sure, please check.

Step-by-step explanation:

(5^2x+2)-(4.5^2x+1)=625

(5^2x)*(5^2)-(4)*(5^2x)*(5)=625

5^2x[5^2-4*5]=625

(5^2x)*5=625

5^2x=625/5

5^2x=125

5^2x=5^3

Since bases are same,

2x=3

x=3/2

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