Math, asked by sam2612, 2 months ago

If 5^2x=36, find the value of 5^-x​

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Answers

Answered by gklmukherjee
0

Answer:

5

2

x−3

×3

2x−8

=4×9

2

x−3

×3

2x−8

=2

2

×3

2

2

x−5

×3

2x−10

=1

x=5

as RHS is 1, the powers have to be zero on the LHS as anything raise to 0 is always 1

Thus x−5=0→x=5

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