if √(5)+√(3)/√(5)−√(3)=a+b√15 find the value of a and b
Answers
Answered by
16
(√5 + √3)^2 / (√5)^2 -(√3)^2
5+3+2√15/ 5-3
8+2√15 /2
4+√15=a+ b√15
a=4
b=1
5+3+2√15/ 5-3
8+2√15 /2
4+√15=a+ b√15
a=4
b=1
Mohit123Sharma:
thanks a lot
Answered by
28
Hi...☺
Here is your answer....✌

Now,
We have
4 + √15 = a + b√15
By comparing
We get,
a = 4 , b = 1
Here is your answer....✌
Now,
We have
4 + √15 = a + b√15
By comparing
We get,
a = 4 , b = 1
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