If 5+√3/√7−43√=x+3–√ y find x and y
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[math]\begin{align*} \left(\sqrt x + \frac{1}{\sqrt x}\right)^2 & = x + 2 + \frac{1}{x} \\ & = (7+4\sqrt3) + 2 + \frac{1}{7+4\sqrt3} \\ & = (7+4\sqrt3) + 2 + (7-4\sqrt3) \\ & = 16 \end{align*}[/math]
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