Math, asked by het20185, 3 months ago

If (5, 3) is the solution of the equation 2

x + 3y +

k = 0 and (

m, 5) is also the solution of it then

m

= ......... .​

Answers

Answered by hdabas2001
0

Step-by-step explanation:

On putting (5,3) in equation-

2x+3y+k=0

2×5+3×3+k=0

10+9+k=0

k=-19

therfore, on putting (m,5) in the equation-

2x+3y+k=0

2×m+3×5+(-19)=0

2m+15-19=0

2m-4=0

2m=4

m=4/2

m=2

Answered by manya9113
0

Answer:

m=2

Step-by-step explanation:

2x + 3y +k = 0

putting x=5 and y=3 because (5,3)is a solution.

2×5 + 3×3 +k = 0

10+9+k=0

k = -19

then equation becomes

2x+3y-19=0

putting x=m and y= 5 because it is also a solution.

2×m + 3×5 -19 = 0

2m +15-19 = 0

2m -4 = 0

2m = 4

m= 4/2

m=2

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