Question

If (5^3)^x+1 = (125)^-2 than find the value of x

Answer 1

Solution :

Given (5³)^x+1 = ( 125 )^-2

=> ( 5³ )^x+1 = ( 5³ )^-2

=> x + 1 = -2

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We know the Exponential Law

If a^m = a^n then m = n

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=> x = -2 - 1

=> x = -3

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Answer 2

$( { {5}^{3}) }^{x + 1} = {125}^{ - 2} \\ find \: x = what \\ let \: us \: equate \: the \: bases \\ ({ {5}^{3} })^{x + 1} = ({ {5}^{3} })^{ - 2} \\ or \: {125}^{x + 1} = {125}^{ - 2} \\ now \: let \: us \: equate \: the \: powers \\ x + 1 = - 2 \\ x = - 2 - 1 \\ x = - 3 \: (ans)$
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