Question

If 5(3x + 4) - 8(6r + 7) = 9x - 8, then
what is the value of (x2 - 2x + 1)?

Answer 1

Step-by-step explanation:

$5(3x + 4) - 8(6 + 7) = 9x - 8 \\ 15x + 20 - 48 - 56 - 9x + 8 = 0 \\ 6x - 76 = 0 \\ x = \frac{76}{6} \\ x = \frac{38}{3} \\ \\ {x}^{2} - 2x + 1 = { \frac{38}{3} }^{2} - 2 \times \frac{38}{3} + 1$