If 5. ⁴pᵣ = 6. ⁵pᵣ₋₁ then value(s) of 'r'
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Step-by-step explanation:
5(4!)= 6×5!
(4-r)! (6-r)!
5×4! =6×5×4!
(4-r)! (6-r)(5-r)(4-r)!
(6-r)(5-r)=6
30-11r+r²=6
r²-11r+24=0
r²-8r-3r+24=0
r(r-8)-3(r-8)=0
(r-3)(r-8)=0
r=3 or 8
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