If 5−4x × 5(x2+4) = 1, then find the value of ‘x’.
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Given: (5x+2),(4x−1) and (x+2) are terms in AP.
So, d=(4x−1)−(5x+2)=(x+2)−(4x−1)
2(4x−1)=(x+2)+(5x+2)
8x−2=6x+2+2
8x−2=6x+4
8x−6x=4+2
or x=3
The value of x is 3.
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