If (–5, –5) is the solution of the system of equations
3x + 4y + 2p – q = 0 and 4x + 3y + q – 3r = 0,
then r is always equal to
(1)
1( )
3 q p (2)
2 ( )
3 q p
(3)
1(3 2 )
2 q p (4) 3 (2 )
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although.. options are not clear to me... but procedure will b same
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