Math, asked by tavishchhikara23, 8 months ago

If 5 Δ 6 = 1331, 6 Δ 1 = 343, and 2 Δ x = 729, then determine the value of x.

Answers

Answered by Teenacharan
2

Answer:

x=9

Step-by-step explanation:

x=9

as we can see the cubes

1331=11cube,343=7cube and 729=9cube

Answered by pulakmath007
0

The value of x = 7

Given :

5 Δ 6 = 1331 , 6 Δ 1 = 343 , and 2 Δ x = 729

To find :

The value of x

Solution :

Step 1 of 2 :

Find the pattern

5 Δ 6 = 1331 = 11³ = (5 + 6)³

6 Δ 1 = 343 = 7³ = (6 + 1)³

So the pattern is as below

a Δ b = (a + b)³

Step 2 of 2 :

Find the value of x

2 Δ x = 729

⇒ (2 + x)³ = 729

⇒ (2 + x)³ = 9³

⇒ 2 + x = 9

⇒ x = 9 - 2

⇒ x = 7

Hence the required value of x = 7

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