If 5*6 is exactly divisible by 3
then the least value of x is
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5×6=30
30÷3=10
so the least value of x is 1
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Answer:
We know that the sum of the digits of a number is divisible by 3 then the whole number is divisible by 3
5+x+6 = multiple of 3
11+x= 0, 3, 6, 9….
11+x= 12
∴ x=12-11 = 1
The least value of x is 1
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