Question

if 5/7 of a number exceeded by 65 gives 80 find the number

Answer 1

Hi ,

Let the number = x

5/7 of a number = 5x / 7

5x / 7 exceeded by 65 = 80

5x / 7 + 65 = 80

5x / 7 = 80 - 65

5x / 7 = 15

x = 15 × ( 7 / 5 )

x = 3 × 7

x = 21

Therefore ,

Required number = x = 21

I hope this helps you.

:)

Answer 2

$\large {\underline{\sf{ Answer:- }}}$

The value of the number which exceeds 5/7th of the number by 65 is 21.

$\large {\underline{\sf{ To \: find:- }}}$

The value of the number

$\large {\underline{\sf{ Explanation:- }}}$

Let the number be x.

$5/7 \: \bf{th \: of \: the \: number} = \frac {5}{7} \times x$

According to the question,

The 5/7th of the number gives 80 when added with the number 65. Hence, the term will be:

$\begin{gathered}\frac {5}{7} \times x+65=80\\\\\frac {5}{7} \times x= 80-65=15\\\\x= \frac {105}{5} =21\\\\x=21\end{gathered}$

Hence, the value of the number which exceeds 5/7th of the number by 65 is 21.

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