if 5(-8+6i)/(1+i)=a+ib then a,b
fiercespartan:
Looking at the question, when I try to solve it, I get the answer as 'undefined'
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rationalise denominator
5(-8+6i)×(1-i)÷(1+I)(1-i)=a+ib
5(-8+8i+6i+6)÷(1+1)=a+ib
5÷2(-2+14i)=a+ib
5(-1+7i)=a+ib
a=-5
b=35
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