Question

if 5 ampere of current is passed through a solution for 10 hours then the number of electons flown through the solution is (charge of electron =1.6*10-19)

Answer 1

Given :-

Current = 5A

Time = 10 × 60 × 60 seconds

To Find :-

Number of electrons

Solution :-

We know :-

Q = It

• I denotes current
• t denotes time
• Q denotes charge

Substitute the values :-

$: \implies \sf Q = 5 \times 10 \times 60 \times 60$

$: \implies \sf Q = 180000$

Also we know :-

Q = ne

• n denotes number of electrons
• e denotes charge of one electron

$: \implies \sf n = \dfrac{Q }{e}$

$: \implies \sf n = \dfrac{180000}{1.6 \times {10}^{ - 19} }$

$: \implies \sf n = 112500 \times {10}^{19}$

Number of electrons :- 1125 × 10^21

Answer 2

Answer:

Given :-

• 5 Ampere of current is passed through a solution for 10 hours.
• Charge of electron = 1.6 × 10-¹⁹.

To Find :-

• What is the number of electrons flow through the solution.

Formula Used :-

$\clubsuit$ Current Formula :

$\mapsto \sf\boxed{\bold{\pink{I =\: \dfrac{Q}{t}}}}$

where,

• I = Current
• Q = Charge
• t = Time

$\clubsuit$ Quantity of Charge Formula :

$\mapsto \sf\boxed{\bold{\pink{Q =\: Ne}}}$

where,

• Q = Quantity of Charge
• N = Number of electrons or protons
• e = Charge of electrons or protons (1.6 × 10-¹⁹ C)

Solution :-

First, we have to convert time hours into seconds :

As we know that :

↦ 1 hours = 60 minutes

↦ 1 minutes = 60 seconds

Hence, 1 hours will be :

↦ 1 hours = 60 minutes

↦ 1 hours = 60 × 1 minutes

↦ 1 hours = 60 × 60 seconds

➠ 1 hours = 3600 seconds

Hence, the time will be :

$\implies \sf Time =\: 10\: hours$

$\implies \sf Time =\: 10 \times 3600\: seconds\: \: \bigg\lgroup \sf\bold{\pink{1\: hours =\: 3600\: seconds}}\bigg\rgroup$

$\implies \sf\bold{\purple{Time =\: 36000\: seconds}}$

First, we have to find the charge :

Given :

$\bigstar\: \: \bf{Time =\: 36000\: seconds}$

$\bigstar\: \: \bf{Current =\: 5\: Ampere}$

According to the question by using the formula we get,

$\implies \sf 5 =\: \dfrac{Q}{36000}$

By doing cross multiplication we get,

$\implies \sf Q =\: 5 \times 36000$

$\implies \sf \bold{\green{Q =\: 180000\: C}}$

Now, we have to find the number of electrons flow through the solution :

Given :

$\bigstar\: \: \bf Charge =\: 180000\: C$

$\bigstar\: \: \bf Charge\: of\: electron\: =\: 1.6 \times 10^{- 19}$

According to the question by using the formula we get,

$\longrightarrow \sf 180000 =\: N \times 1.6 \times 10^{- 19}$

$\longrightarrow \sf \dfrac{180000}{1.6 \times 10^{- 19}} =\: N$

$\longrightarrow \sf 112500 \times 10^{19} =\: N$

$\longrightarrow \sf 1125 \times 10^{(19 + 2)} =\: N$

$\longrightarrow \sf 1125 \times 10^{21} =\: N$

$\longrightarrow \sf\bold{\red{N =\: 1125 \times 10^{21}}}$

${\small{\bold{\underline{\therefore\: The\: number\: of\: electrons\: flow\: through\: the\: solution\: is\: 1125 \times 10^{21}\: .}}}}$