Question

if 5 cos θ = 6 sin θ; evaluate:

1)tan θ

2) 12 sin θ -3 cos θ/ 12 sin θ + 3 cos θ
answer it fast!!

Answer 1

Answer:

5cosQ=6SinQ

5=6tanQ

1) TanQ=5/6

2)12sinQ-3cosQ/12sinQ+3cosQ

Divide numerator and denominator by 3cosQ

=4tanQ-1/4tanQ+1

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