If 5 cosA=7sinA then the value of 7sinA+5cosA divided by 5sinA+7cosA
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5cosA=7sinA
or, cosA=7sinA/5
∴, (7sinA+5cosA)/(5sinA+7cosA)
=(7sinA+7sinA)/(5sinA+7×7sinA/5)
=14sinA/(5sinA+49sinA/5)
=14sinA/{(25sinA+49sinA)/5}
=(14sinA×5)/(74sinA)
=70sinA/74sinA
=35/37 Ans.
or, cosA=7sinA/5
∴, (7sinA+5cosA)/(5sinA+7cosA)
=(7sinA+7sinA)/(5sinA+7×7sinA/5)
=14sinA/(5sinA+49sinA/5)
=14sinA/{(25sinA+49sinA)/5}
=(14sinA×5)/(74sinA)
=70sinA/74sinA
=35/37 Ans.
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0
Step-by-step explanation:
right answer is 35/37 see the answer in photo with explain
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