if 5 is a root of equation x^2-4x+k=0 find the value of k and the other root
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Answer:
value of k will be -5
and other root will b -1
Step-by-step explanation:
here... the root given is 5
so we will put 5 in the value of x
x^2-4x+k=0
5^2-4*5+k=0
25-20+k=0
hence...k=-5
now the quadratic equation will b
x^2-4x-5
by factorising it... v will get
x^2-5x+x-5
x(x-5)+1(x-5)
soo... x=-1
x=5
hope it will help u
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