Math, asked by MrBlackCoffee, 10 months ago

if 5 is a root of equation x^2-4x+k=0 find the value of k and the other root
it​

Answers

Answered by ayushsiwal
1

Answer:

value of k will be -5

and other root will b -1

Step-by-step explanation:

here... the root given is 5

so we will put 5 in the value of x

x^2-4x+k=0

5^2-4*5+k=0

25-20+k=0

hence...k=-5

now the quadratic equation will b

x^2-4x-5

by factorising it... v will get

x^2-5x+x-5

x(x-5)+1(x-5)

soo... x=-1

x=5

hope it will help u

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Answered by XxCharmingGuyxX
0

ur answer see in attcement

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