If -5 is a root of quadratic equation 2x^2+px-15=0 and the quadratic equation p(x^2+x) +k=0 has equal roots. find the value of k.
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Answer:
k = -140
Explanation:
-5 is a root of quadratic equation.
Therefore, x = -5
2x^2+px-15=0 (putting x = -5)
2X(-5)^2 + pX(-5) - 15 = 0
(2X25) - 5p - 15 = 0
50 - 5p - 15 = 0
-5p + 35 = 0
-5p = -35
p = -35/-5
p = 7
now,
p(x^2+x) +k = 0 ( put x = -5 & p = 7)
7 [(-5^2) + (-5)] + k = 0
7 (25-5) +k = 0
7 X 20 + k = 0
140 + k = 0
k = -140
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