Question

If -5 is a root of the quadratic equation 2x^2+px-15=0 and quadratic equation has equal roots, find value of x.

Answer 1

Answer:

$\large\boxed{\star\:\:p=7\:\:\star}$

Step-by-step explanation:

✧Given:-

(-5) is a root of the quadratic equation 2x²+px-15=0 and quadratic equation have equal roots.

∴This Quadratic Equation have roots as (-5),(-5) as they are equal.

✧To Find:-

The Value of p.

✧Solution:-

⇒ p(x)=2x²+px-15=0

⇒ p(-5)=[2×(-5)²]+[p×(-5)]-15=0

⇒ (25×2)-5p-15=0

⇒ 50-15=5p

⇒ 5p=35

$\implies\:p=\frac{35}{5}$

$\implies\:\boxed{p=7}$