Question

If -5 is a root of the quadratic equation 2x^(2)+px-15=0 , then​

Answer 1

2x^2+px-15=0

2×-5^2+p×-5-15=0

2×25+-5p -15 =0

50 -5p - 15=0

35-5p=0

-5p=-35

p=7

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Answer 2

Given :

• If -5 is a root of the quadratic equation 2x² + px - 15 = 0

To find :

• value of P

Solution :

2x² + Px - 15 = 0

Since,-5 is the root of this quadratic equation.

So, 2 x (-5)² +p(-5) - 15 = 0

50 + 5p - 15 = 0

50 = 5p - 15

5p = 50 - 15

5p = 35

p = 35/5

p = 7

∴ value of p is 7