if (-5) is a zero of a polynomial p(x)=xto the power 2 +11x+k. then calculate the value of k
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ATQ, -5 is a zero of polynomial p(x) = x² + 11x + k
so the remainder must come zero when p(x) is divided by -5
putting value -5 in p(x)
➡ p(-5) = (-5)² + 11(-5) + k = 0
➡ p(-5) = 25 - 55 + k = 0
➡ p(-5) = -30 + k = 0
➡ k = 30
verification :-
LHS = (-5)² - 11(-5) + 30
= 25 - 55 + 30
= -30 + 30
= 0
RHS = 0 (since remainder is 0 when polynomial is divided by it's zero)
LHS = RHS
hence, the value of k is 30
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