Question

if 5 is a zero of x cube+kx square +2x +8​

Answer 1

Answer:

p(x) = x³ + kx² + 2x + 8

p(5) = 0

p(5) = 5³ + 25k + 10 + 8

125 + 25k + 18 = 0

143 + 25k = 0

25k = -143

k = -143/25

Step-by-step explanation:

Answer 2

p(x) =x*³+kx*²+2x+8

x= 5

p(5)=5*³+k5*²+2×5+8=0( as 5 is zero of polynomial)

=125+25k+18=0

=133+25k=0

=25k= -143

=k = -143/25

=k=-5.72

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