Question

If '5' is a zero of x + Kx²+2x+8
then find value of k'.​

Answer 1

Answer:

-23/25

Step-by-step explanation:

Given

p(x)=x + kx²+2x+8

p(5)=0

Therefore,

p(5)=(5) + k(5)²+2(5)+8=0

=>5 + 25k + 10 + 8 = 0

=>23+25k = 0

=>25k = -23

=>k = -23/25