If 5 is one of the zeroes of polynomial p(x)=xcude-6xsquare+ax+ 10, then a =
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Answer:
a = -57
Step-by-step explanation
Let x = 5
Therefore 5^3 +6 x 5^2 + 5a +10
125 + 150 + 5a + 10 = 0
285 + 5a = 0
a = -57
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