Question

if 5 is one of the zeros of polynomial p(x)=x^3-6x^2+ax+10 then a=​

Answer 1

Answer:

if 5 is zero of the polynomial then

p(5)=0

${5}^{3} - 6 {(5)}^{2} + a \times 5 + 10 = 0 \\ 125 - 25 \times 6 + 5a + 10 = 0 \\ 125 - 150 + 5a + 10 = 0 \\ - 25 + 5a + 10 = 0 \\ 5a - 15 = 0 \\ 5a = 15 \\ a = 3$

Answer 2

Step-by-step explanation:

if 5 is the zeroes of the polynomial.

then by putting the value of 5 in the polynomial we get zero

p(5)=0

${5}^{3} - 6 \times {5}^{2} + 5a + 10 = 0$

125-6×25+5a+10=0

125-150+10+5a=0

-25+10+5a=0

5a=25-10

5a=15

a=3. Answer