if -5 is root of a quadtric equation 2x²+px-15
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Solution :
Given Quadratic equation 2x²+px-15=0
If ( -5 ) is a root of the equation , then
substitute x = -5 in the equation, we
get
2( -5 )² + p( -5 ) - 15 = 0
=> 50 - 5p - 15 = 0
=> 35 - 5p = 0
=> -5p = -35
=> p = ( -35 )/( -5 )
=> p = 7
Therefore ,
p = 7
•••••
Given Quadratic equation 2x²+px-15=0
If ( -5 ) is a root of the equation , then
substitute x = -5 in the equation, we
get
2( -5 )² + p( -5 ) - 15 = 0
=> 50 - 5p - 15 = 0
=> 35 - 5p = 0
=> -5p = -35
=> p = ( -35 )/( -5 )
=> p = 7
Therefore ,
p = 7
•••••
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