if -5 is the root of the quadratic equation 2 X square + px - 15 is equal to zero and the quadratic equation p(x2+x)+k is equal to zero has equal roots find the value of k
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putting X= -5 in given quadratic equation
2(-5)^2 +p(-5) -15 =0
50-5p-15=0
35-5p=0
35=5p
p=7
Substituting p=7 in 2nd polynomial
7(x^2+x)+K
7x^2 + 7x + k
for equal roots D=0
B^2 - 4AC = 0
(7)^2 - 4*7*k = 0
49 - 28k = 0
49 = 28k
divide by 7 both sides
7= 4k
k = 7/4
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