Question

if 5 is the zero of the polynomial x^2-kx-15, find the value of K
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Answer 1

x=5

x=5putting x in equation

x=5putting x in equationp(x)=x^2-kx-15=0

x=5putting x in equationp(x)=x^2-kx-15=0=(5)^2-k(5)-15=0

x=5putting x in equationp(x)=x^2-kx-15=0=(5)^2-k(5)-15=0=25-5k-15=0

x=5putting x in equationp(x)=x^2-kx-15=0=(5)^2-k(5)-15=0=25-5k-15=0=10-5k=0

x=5putting x in equationp(x)=x^2-kx-15=0=(5)^2-k(5)-15=0=25-5k-15=0=10-5k=0=-5k=-10

x=5putting x in equationp(x)=x^2-kx-15=0=(5)^2-k(5)-15=0=25-5k-15=0=10-5k=0=-5k=-10=k=-10/-5

x=5putting x in equationp(x)=x^2-kx-15=0=(5)^2-k(5)-15=0=25-5k-15=0=10-5k=0=-5k=-10=k=-10/-5=k=2

x=5putting x in equationp(x)=x^2-kx-15=0=(5)^2-k(5)-15=0=25-5k-15=0=10-5k=0=-5k=-10=k=-10/-5=k=2Value of k is 2

I hope it halp u

Answer 2

Explanation:

x=5

putting x in equation

p(x)=x^2-kx-15=0

=(5)^2-k(5)-15=0

=25-5k-15=0

=10-5k=0

=-5k=-10

=k=-10/-5

=k=2

Value of k is 2

Hope its helpful for you dear ❤❤