Question

If-5 is the zero of the polynomial x3-5x2 - 29x + 105 Then find the other two roots.​

Answer 1

Answer:

in cubic polynomial,

-5 is the zero of the polynomial,

therefore, (x+5) is the factor of x^3-5x^2-29x+105

when this polynomial x^3-5x^2-29x+105 is divided by (x+5)

then,

x^3-5x^2-29x+105 = (x^2-10x+21) ( x+5)

=x^2-3x-7x+21 (x+5)

= x(x-3) -7(x-3) (x+5)

= (x-3) (x-7) (x+5)

hence zeroes of the polynomial are:

x=3

x=7

x=-5