If 5 is zero of x3+kx2+2
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p(x) = x³+kx²+2
If 5 is a zero then, p(5) = 0
p(5) = 0
(5)³+k(5)²+2 = 0
125+25k+2 = 0
127+25k = 0
25k = -127
k = -127/25
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