if 5 kg wooden block kept on the top of a table . Its dimension are 30 cm × 20 cm × 5 cm . find the pressure exerted by the wooden block on the table top , if it is made to lie on the table top with its side of demnsions .
a. 30 cm × 20 cm
b. 30 cm × 5 cm . ( take g = 10 meter per second square )
Answers
Answered by
3
when it lies 30 *20 it's area will be 600 cm^2
and force will be 5*10 = 50N
so pressure will be (50/ 600)* 10000
p= 2500/3 Pascal
in the second case area will be 150/10000 m^2
p= (50 / 150)*10000
p= 10000/3 Pascal
and force will be 5*10 = 50N
so pressure will be (50/ 600)* 10000
p= 2500/3 Pascal
in the second case area will be 150/10000 m^2
p= (50 / 150)*10000
p= 10000/3 Pascal
udita74:
thanks so much
Answered by
1
pressure=force/area.Here the force acting is weight of body and only area is varying. weight=5x10 =50N a} Area = 20x10 square cm=200/10000 sq m=0.02 pressure=50/0.02=2500 Pa Similarly calculate the area IN second case ,convert it into square metre
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