If 5 l of SO2 is burnt in excess air to form so3 what is the volume of so3 formed
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Stoichiometrically, 1.34 moles of O2 upon reacted with SO2 produce 2/1 x 1.34 moles of SO3 or 2.68 moles of SO3. So, the volume of SO3 generated will be (2.68 moles/1 mole) x 22.4 L = 60.03 L SO3.
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Explanation:
, the volume of SO3 generated will be (2.68 moles/1 mole) x 22.4 L = 60.03 L
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