If 5<2a+1<11 and 4<3b-2<19 ,find minimum value of 2b/3+a
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Solution
[ 8−11102−1]
Since, 2A+3B=[ 23 −1245] …………(1)
A+2B=[ 510632 ] ………….(2)
2× Equation (2)− Equation (1)
⇒2A+4B−2A−3B=[ 10−2 2−3 0+1 12−2 6−4 4−5 ]
⇒B=[ 8−11102−1 ]
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Step-by-step explanation:
[ 8−11102−1]
Since, 2A+3B=[ 23 −1245] …………(1)
A+2B=[ 510632 ] ………….(2)
2× Equation (2)− Equation (1)
⇒2A+4B−2A−3B=[ 10−2 2−3 0+1 12−2 6−4 4−5 ]
⇒B=[ 8−11102−1 ]
Was this answer helpful?
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