Question

if 5 M and 15 M high are 100 M apart then find the height of the point of intersection of the line joining the point of each pole to the foot of the opposite pole

Answer 1

Good Evening Student,

Assume that 5 m high pole is at the origin and the 15 m high pole is at x = 100 m
Then, the line from the base of the 5 m pole to the top of 15 m high pole is 

⇒ y = 15x/100 ---(i)

The line from the base of 15 m high pole to the top of 5 m high is

⇒ y = - 5x/100 + 5 --(ii)

On Equating,

⇒ 15x/100 = - 5x/100 + 5 

⇒ 0.15x = - 0.05x + 5

⇒ 0.15x + 0.05x = 5

⇒ 0.2x = 5

⇒ x = 5/0.2

⇒ x = 25

Putting the value of x = 25 in eqn. (i)

⇒ y = 15x/100

⇒ y = (15 × 25)/100

⇒ y = 375/100

⇒ y = 3.75 m

So, height of point of intersection is 3.75 m

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