if 5 m tall object is placed at a distance of 30 cm from a convex mirror of focal length 15cm find the position size and the nature of the image formed
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h=5m=500cm
u=-30cm
f=15cm
1/15=1/v+1/-30
1/15-1/-30=1/v
1/v=-30-15/-450
v=-450/-45=10cm
Position=+10cm
h'/h=-v/u
h'/500=-10/-30
h'=-5000/-30
h'=166.67cm
Size=166.67cm
Nature:virtual erect and diminished
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