Question

If 5 m3 of a certain liquid weighs 40 kN, calculate the mass density (kg/m3) and specific gravity of the liquid. Consider g as 9.81m/s2.​

Answer 1

what is m3 we know only pubg

Answer 2

Given:

Weight of certain liquid (W) = 40 kN = 40,000 N

It's volume = $\bold{5m^{3}}$

Acceleration due to gravity (g) =  $\bold{9.8 ms^{-2}}$

To Find:

Mass density ($kgm^{-3}$) and specific gravity of the given liquid.

Solution:

Before going to the solution we have to know about mass density and specific gravity. Mass density is defined as the ratio of mass of the substance to the volume. Whereas specific gravity is the ratio of weight of the substance to weight of equal volume of water at $4^{0}C$.

∴Mass of the liquid = $\frac{40,000}{9.81}kg$ = 4,077.5 kg

Now, Mass density of the liquid (${\rho}$) = ${\frac{\bold{4,077.5 kg}}{\bold{5m^{3}}}$ =  ${815.5} kg m^{-3}$

And specific gravity of the liquid = $\frac{815.5}{997 }$ = 0.818 (∵ Mass density of water is

                                                                                            ${997} kg m^{-3}$)

∴Mass density of the liquid  is $\bold{{815.5} kg m^{-3}}$ and specific gravity is 0.818 .