Question

if 5 man and 3 boys can reap 23 hectares in 4 days and if 3 man and 2 boys can reap 7 hectares in 2 days. How many boys must assist 7 men in order that they may reap 45 hectares in 6 days ?

Answer 1

Ans: 2
hope it helps maybe some error but final answer is 2

Let work done by 1 man in 1 day be m
work done by 1 boy in 1 day be b

4(5m+3b)=23⇒20m+12b=23  ⋯(1)

2(3m+2b)=7⇒6m+4b=7  ⋯⋯(2)

(2)×3⇒  18m+12b=21  ⋯(3)

(1)−(3)⇒  2m=2⇒m=1

From (2),
6+4b=7⇒b=146+4b=7⇒b=14

Let required number of boys be xx
6(7×1+x×14)=456(7+x4)
=457+x4=7.5x4=0.5
x=2

Answer 2

Answer:

Let work done by 1 man in i day be a

and Let work done by 1 boy in 1 day be b

From the given information :-

4(5a+ 3b) = 23

20a + 12b = 23....(1)

2(3a + 2b) = 7

6a + 4b = 7 ....(2)

By solving (1) & (2), we get

a = 1, b = 1/4

Let the number of required boys = m

6(7 1 + m × 1/4) = 45

=> m = 2.

~ Nikhra♥