If 5 men can do a piece of work in 6 days whille 10 women can do it in 5
days, then in how many days can 5 women and 3 men do it?
Answers
Answered by
0
Answer:
The work requires 5x6 = 30 man-days.
The work requires 10x5 = 50 woman-days.
1 man does (1/30)th of the work in 1 day and 3 men can do (1/10)th of the work in a day.
1 woman does (1/50)th of the work in 1 day and 5 women can do (1/10)th of the work in a day.
So 3 men and 5 women can do (1/10)+(1/10) = (1/5)th of the work in 1 day.
Thus 3 men and 5 women will complete the same work in 5 days.
Answered by
0
Answer:
B) 5 days
Description for Correct answer:
5M×6 days=10W×5 days5M×6 days=10W×5 days
3M = 5W
MW=53MW=53
mb=21mb=21
1M (work) = 5 units/day
1W (work) = 3 units/day
Hence,
Total work
=(5M×6)=5×5×6(5M×6)=5×5×6
=150 units
Required Time for
(5M+3W)(5M+3W)
=Total workWork done/dayTotal workWork done/day
150(5×3+3×5)=15030=5150(5×3+3×5)=15030=5 days
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