Question

If 5 men can paint a room 50 m long, 6 m high and 13 m wide working 10 hours
per day in 6 days, then how many days of 9 hours each will 10 men need to paint
a room 40 m long, 7 m high and 10 m wide. (Assume all the walls and ceiling are
painted leaving the floor)​

Answer 1

Answer:

25*2=50/2=25*3=75/25=3

Step-by-step explanation:

Answer 2

Given:

Dimensions of the room = 50x6x13 m

time taken by 5 men to complete the task = 6 days

number of hours of work each day = 9 hours

To find:

Time taken to complete the second room by 10 men.

Solution:

total surface area of the first room painted = 50 x 13 + 2( 50 x 6 + 13 x 6)

= 650 + 2( 300 + 78)

= 1406 $m^{2}$

Number of days taken to complete the task = 6 days

number of hours worked per day = 10 hours

total number of hours taken = 60 hours

Time taken by 5 men to paint 1 $m^2$ area = $\frac{60}{1406}$ hours

Now,

Dimensions of the second room = 40 x 7 x 10

Area of the second room to be painted = 40 x 10 + 2(40 x 7 + 7 x10)

= 400 + 2(280 + 70)

= 1100 $m^2$

Number of hours taken by 5 men to paint 1100 $m^2$ area = $\frac{60}{1406}$ x 1100

= 46.94 hours

So, time taken by 10 men to complete this task = $\frac{46.94}{2}$ = 23.47 hours

So, if 9 hours of work is done each day, number of days required = $\frac{23.47}{9}$

= 2.6 Say 3 days

Therefore, 3 days are required to complete the task.