Question

If 5% NaCl solution is used for
regeneration of zeolite, calculate amount
of CaCo3 equivalent hardness which car
be removed by one liter of NaCl
solution​

Answer 1

Answer:

It is calculated using Eq (2c): NCH (mg/L) = Total hardness-Carbonate hardness (2c) Page 2 Page 2 Determination of Hardness: Hardness is expressed as mg/L CaCO3.

Answer 2

Answer:

The amount of $CaCO_{3}$ is $214$ milligrams.

Explanation:

The mole, image mol, is the SI base unit of the quantity of substance. The amount quantity of the substance is the degree to which a number of simple entities of a given substance is in an item or sample.

If the efficiency is considered $100 \%$, then

$\mathrm{n}(\mathrm{Na})=0.0855 \mathrm{~mol}$

$\mathrm{n}(\mathrm{Ca})=0.0855 / 2=0.0428 \mathrm{~mol}$

$\mathrm{m}\left(\mathrm{CaCO}_{3}\right)=4.28 \mathrm{~g}=4280 \mathrm{mg}$

5% NaCl solution is used for regeneration of zeolite:

5% of 4280:

$=4280\times\frac{5}{100}\\ =214mg$