Question

If 5^p = 7^q =35^-r then value of 1/p +1/q +1/r is

Answer 1

i guess it helps your question

Answer 2

Let 5^p = 7^q = 35^-r = k

5^p = k

5 = k^1/ p………..(1)


7^q = k

7 = k^1/q………….(2)


Now 35^-r = k

35= k^-1/r


(5 x 7) = k^-1/r

(k^1/p ) x (k^1/q ) = k^-1/r ( from eq. (1) and (2) )



k ^(1/p +1/q) = k^-1/r

1/p +1/q = -1/r


(1/p + 1/q + 1/r) =0

Hence, the value of 1/p + 1/q + 1/r = 0.

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