Question

If 5 resistor, each of value 0.2 ohm are connected in series what will be the resultant

resistance

9. 1 ohm

10. 10 ohm

11. 6 ohm

12. 8 ohm​

Answer 1

Answer:

The resultant resistance would be R1+R2+...+R5

=0.2+0.2+... 5 times=0.2×5 = 1 ohm

Answer 2

Answer:

As per the law of combination of resistances in series,

R=R

1

+R

2

+R

3

+R

4

+R

5

R=0.2+0.2+0.2+0.2+0.2

=1ohm

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