Question

If 5 sec 0 - 12 cosec 0 = 0, find the values of sec 0,
cos and sin 0.​

Answer 1

Step-by-step explanation:

5 secФ - 12 cosecФ = 0

5 secФ = 12 cosecФ

\frac{5}{12} = \frac{cosec}{sec}

\frac{5}{12} = \frac{ \frac{hypotenuse}{perpendicular} }{ \frac{hypotenuse}{base} }

\frac{5}{12} = \frac{ \frac{1}{perpendicular} }{ \frac{1}{base} }

\frac{5}{12} = \frac{1}{perpendicular} × \frac{base}{1}

\frac{5}{12} = \frac{base}{perpendicular}

Now,

Let base be 5x

perpendicular be 12x

Answer 2

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