Question

if 5 sec ϴ - 12 cosec ϴ=0 find the values of sec ϴ cos ϴ and sin ϴ

Answer 1

5 secФ - 12 cosecФ = 0 

5 secФ = 12 cosecФ

$\frac{5}{12} = \frac{cosec}{sec}$

$\frac{5}{12} = \frac{ \frac{hypotenuse}{perpendicular} }{ \frac{hypotenuse}{base} }$

$\frac{5}{12} = \frac{ \frac{1}{perpendicular} }{ \frac{1}{base} }$


$\frac{5}{12} = \frac{1}{perpendicular}$×$\frac{base}{1}$


$\frac{5}{12} = \frac{base}{perpendicular}$



Now,
Let base be  5x 
perpendicular  be 12x 

             By Pythagoras Theorem,


$(5x)^2 + (12x)^2 = (hypotenuse)^2$

$25x^2 + 144x^2 = (hypotenuse)^2$

$169x^2 = (hypotenuse)^2$

$\sqrt{169x^2} = hypotenuse$

$\sqrt{(13x)^2} = hypotenuse$

13x = hypotenuse 


______________________


             Then,


secФ =$\frac{hypotenuse}{base} = \frac{13x}{5x} = \frac{13}{5}$

cosФ = $\frac{1}{sec} = \frac{5}{13}$

sin Ф = $\frac{perpendicular}{hypotenuse} = \frac{12x}{13x} = \frac{12}{13}$




i hope this will help you



-by ABHAY

Answer 2

Answer:

check the pic above

Step-by-step explanation:

PLEASE MARK BRAINLIEST