Question

If 5 sec ø = 13 then prove that sin ø = 12/13

Answer 1

$\underline{\bold{Answer:-}}$




Given

5 secø = 13


secø = 13 / 5 = H / B

Here Hypotenuse ( H ) = 13 , Base ( B ) = 5 , Perpendicular ( P ) = ?

By pythagoras theorem, we have

P = √H^2 - B^2

=> √ ( 13)^2 - ( 5 )^2

=> √ 169 - 25

=> √ 144

=> 12



Here Hypotenuse ( H ) = 13 , Base ( B ) = 5 , Perpendicular ( P ) = 12



Sinø = P / H = 12 / 13


Hence, it is proved ✔ ✔













$\textbf{Hope it helps!}$

Answer 2

hey!


here is answer

given

5secø=13


hence
secø=13/5


sec ø= hypotenuse/ base


sec ø= 13/5

here we get

hypotenuse = 13 units

base= 5 units

by Pythagoras theorem

$p = \sqrt{ {h}^{2} - { b}^{2} }$


${p}= \sqrt{ {13}^{2} - {5}^{2} }$


${p} = \sqrt{169 - 25}$

${p}= \sqrt{144}$
$p = 12$

hence

sin ø= p/b


hence

sin ø= 12/13


proved


hope it helps

thanks