if 5 sec theta-12 =0 find the values of sec theta cos theta sin theta
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Cosec ¢ = Hypotenuse / Perpendicular
And,
Sec ¢ = Hypotenuse / Base
Given :- 5 Sec ¢ - 12 Cosec ¢ = 0
5 Sec ¢ = 12 Cosec ¢
Cosec ¢ / Sec ¢ = 5/12
Hypotenuse / Perpendicular / Hypotenuse / Base = 5/12
Hypotenuse / Perpendicular × Base / Hypotenuse = 5/12
Base / Perpendicular = 5/12
Base = 5 and Perpendicular = 12
By Pythagoras theroem ,
( Hypotenuse )² = ( Base )² + ( Perpendicular)²
( Hypotenuse )² = (5)² + (12)²
( Hypotenuse )² = 169
Hypotenuse = √169
Hypotenuse = 13
Therefore,
Sec ¢ = Hypotenuse / Base = 13/5
Cos ¢ = Base / Hypotenuse = 5/13
Sin ¢ = Perpendicular/ Hypotenuse = 12/13
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