Question

If 5 sin 0–12 cos 0 = 0, find the values of sec 0 & cosec 0.​

Answer 1

Answer:

5sinΦ - 12cosΦ = 0

5sinΦ = 12cosΦ

sinΦ/cosΦ = 5/12

tanΦ = 5/12

cotΦ = 12/5

1 + tanΦ^2 = secΦ^2

1 + (5/12)^2 = secΦ^2

secΦ = 13/12

1 + cotΦ^2 = cosecΦ^2

1 + (12/5)^2 = cosecΦ^2

cosecΦ = 13/5